Find the length of segment BC.A) 2n B) √nC) √2nD) [tex]\frac{n\sqrt{2} }{2}[/tex]E) n√2

Answer:DStep-by-step explanation:Since the triangle is right using the cosine ratio to solve for BCnoting that the exact value of cos45° = [tex]\frac{1}{\sqrt{2} }[/tex], socos45° = [tex]\frac{BC}{AC}[/tex] = [tex]\frac{BC}{n}[/tex]Multiply both sides by nn × cos45° = BCn × [tex]\frac{1}{\sqrt{2} }[/tex] = BC[tex]\frac{n}{\sqrt{2} }[/tex] × [tex]\frac{\sqrt{2} }{\sqrt{2} }[/tex] = BCHence BC = [tex]\frac{n\sqrt{2} }{2}[/tex] → D