Martin puts two bowls of fruit out for his friends.The bowl of grapes has 9 green grapes and 16 red grapes. The bowl of tangerines has 7 seeded and 3 seedless tangerines.Martin's friend chooses a random grape and a random tangerine. What is the probability that she chooses a green grape and a seedless tangerine?
Accepted Solution
A:
Answer:Step-by-step explanation:There are two requirements: a green grape and a seedless tangerineFor grapes, total number of grapes is 9+16 = 25 and 9 are greenProb (green grape)=9/25For tangerines, total number of tangerines is 7+3 = 10 and 3 are seedlessProb (seedless tangerine)=3/10Prob (a green grape and a seedless tangerine)=9/25*3/10=27/250